The perimeter of a triangle is 8+13a+7a2 and two of its sides are 2a2

1.	The perimeter of a triangle is 8+13a+7a2 and two of its sides are 2a2 +3a+ 2 and 3a2 – 4a-1.Find the third side of the triangle.
Answer» Step-by-step EXPLANATION: The perimeter of a triangle is 8+13a+7a2 two of its sides are 2a2 +3a+ 2 and 3a2 – 4A-1. Two sides of triangle are given, LET the non given side be x Perimeter of triangle = sum of all sides (2a2 +3a+ 2) + (3a2 – 4a-1) + x = 8+13a+7a2 (4a +3a + 2) +(6a - 4a - 1) + x =8+13a+14a x = 7 + 18a Third side of triangle is 7 + 18a

The perimeter of a triangle is 8+13a+7a2 and two of its sides are 2a2 +3a+ 2 and 3a2 – 4a-1.Find the third side of the triangle.

Answer»

Step-by-step EXPLANATION:

The perimeter of a triangle is 8+13a+7a2

two of its sides are 2a2 +3a+ 2 and 3a2 – 4A-1.

Two sides of triangle are given, LET the non given side be x

Perimeter of triangle = sum of all sides

(2a2 +3a+ 2) + (3a2 – 4a-1) + x = 8+13a+7a2

(4a +3a + 2) +(6a - 4a - 1) + x =8+13a+14a

x = 7 + 18a

Third side of triangle is 7 + 18a