The perimeter of a triangle is 300m. is its side are in a ratio 3:5:7.

1.	The perimeter of a triangle is 300m. is its side are in a ratio 3:5:7. find the area of the triangle
Answer» 3x+5x+7x=300 15x=300 x=20 By using COSINE rule to FIND some ANGLE from the triangle. let a =3x b=5x c=7x a=60 b=100 c=140(We need to find the angle between a and b) c^2=a^2+b^2-2ab cos C ( Find the angle opposite of line c) 19600=3600+10000-[ 2(60)(100) cosC] -6000= 12000cos C C=120 By using formula of Side angle side (AB sin C)/2=(60x100 sin120)/2 =2598.07m^2

The perimeter of a triangle is 300m. is its side are in a ratio 3:5:7. find the area of the triangle

Answer»

3x+5x+7x=300

15x=300

x=20

By using COSINE rule to FIND some ANGLE from the triangle.

let a =3x b=5x c=7x

a=60 b=100 c=140(We need to find the angle between a and b)

c^2=a^2+b^2-2ab cos C ( Find the angle opposite of line c)

19600=3600+10000-[ 2(60)(100) cosC]

-6000= 12000cos C

C=120

By using formula of Side angle side

(AB sin C)/2=(60x100 sin120)/2

=2598.07m^2

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The perimeter of a triangle is 300m. is its side are in a ratio 3:5:7. find the area of the triangle

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