The perimeter of a triangle ABC is 6 times the arithmetic mean of the

1.	The perimeter of a triangle ABC is 6 times the arithmetic mean of the sines of its angles. If the side b is 2, then the angle B is
Answer» ANSWER: P(ABC) = 6× ARITHMETIC mean if angles Arithmetic mean = ANGLE2 +A2+A3 / 3 Sum of 3 angles of a triangle = 180° So , Arithmetic mean = 180/3=60 Perimeter (ABC)= 6× 60= 360units.

The perimeter of a triangle ABC is 6 times the arithmetic mean of the sines of its angles. If the side b is 2, then the angle B is

Answer»

ANSWER:

P(ABC) = 6× ARITHMETIC mean if angles

Arithmetic mean = ANGLE2 +A2+A3 / 3

Sum of 3 angles of a triangle = 180°

So , Arithmetic mean = 180/3=60

Perimeter (ABC)= 6× 60= 360units.

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The perimeter of a triangle ABC is 6 times the arithmetic mean of the sines of its angles. If the side b is 2, then the angle B is

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