The perimeter of a rectangle is 90 in. The length is 3 more than the w

1.	The perimeter of a rectangle is 90 in. The length is 3 more than the width. What is the length?
Answer» Given Perimeter of Rectangle is 90 units . LENGTH is 3 more than the WIDTH. To Find we have to find the length $\sf\huge {\underline{\underline{{Solution}}}}$ Since, perimeter of Rectangle is given and we don't know the length and breadth.So,let us assume the length and breadth some Variable. Let the breadth be 'x' Length is 3 more than the width : Then our Equation BECOMES :3+x *Perimeter of Rectangle= 2(l+b)* Where ,l is the length and b is the breadth => Perimeter of Rectangle= 2(3+x+x) => 90= 2(2x+3) =>90= 4x+6 => 84= 4x => x= 84÷4 x= 21 Hence, breadth is 21 units length = 3+x= 3+21= 24 units Check: Perimeter of Rectangle= 2(24+21) Perimeter of Rectangle=2(45)=90 units. Extra information=> Perimeter is the TOTAL distance occupy by a solid 2D figure around its edge. *Some properties of Rectangl*e: Opposite sides are EQUAL and parallel Both Diagonals bisects each other and are equal in length. The sum of all Interior angles is 360°.

The perimeter of a rectangle is 90 in. The length is 3 more than the width. What is the length?

Answer»

Perimeter of Rectangle is 90 units .

LENGTH is 3 more than the WIDTH.

we have to find the length

$\sf\huge {\underline{\underline{{Solution}}}}$

Since, perimeter of Rectangle is given and we don't know the length and breadth.So,let us assume the length and breadth some Variable.

Let the breadth be 'x'

Length is 3 more than the width :

Then our Equation BECOMES :3+x

Perimeter of Rectangle= 2(l+b)

Where ,l is the length and b is the breadth

=> Perimeter of Rectangle= 2(3+x+x)

=> 90= 2(2x+3)

=>90= 4x+6

=> 84= 4x

=> x= 84÷4

Hence, breadth is 21 units

length = 3+x= 3+21= 24 units

Perimeter of Rectangle= 2(24+21)

Perimeter of Rectangle=2(45)=90 units.

Perimeter is the TOTAL distance occupy by a solid 2D figure around its edge.

Some properties of Rectangle: