.The perimeerand area of the plot.A rectangular garden is 175 m long a

1.	.The perimeerand area of the plot.A rectangular garden is 175 m long and 96 m broad. Find the cost of fencing it at 17.00 permetre. Also, find the cost of ploughing it at 4.50 paise per square metre.Square tiles of side 20 cm are to be laid on the floor of a room 10 m by 4.5 m. How many tiles willanded? Find the cost of putting the tiles at 131.40 per tile.
Answer» EXPLAINED : length = 175m breath =96 area of the RECTANGLE = l×b = 175×96 = 16800 if the COST of fencing in 1m = 17 then the cost of fencing in 16800m = 17×16800 = 285600 and the cost of ploughing in 1m = 4.50 the cost of ploughing in 16800m = 450/100 ×16800 = 175600 area of TILES =s×s = 20×20 = 400 according to the room length the area of tiles =400×10 = 4000 by ADDING in 4.5m = 4000×4.5 = 18000 the tiles will be adding = 18000-4000 = 14000 if the cost of putting the tiles in 1m= 131.40 then the cost of putting the tiles in 14000m = 14000×131.40 = 1839600

.The perimeerand area of the plot.A rectangular garden is 175 m long and 96 m broad. Find the cost of fencing it at 17.00 permetre. Also, find the cost of ploughing it at 4.50 paise per square metre.Square tiles of side 20 cm are to be laid on the floor of a room 10 m by 4.5 m. How many tiles willanded? Find the cost of putting the tiles at 131.40 per tile.

Answer»

length = 175m

breath =96

area of the RECTANGLE = l×b

= 175×96

= 16800

if the COST of fencing in 1m = 17

then the cost of fencing in 16800m = 17×16800

= 285600

and

the cost of ploughing in 1m = 4.50

the cost of ploughing in 16800m = 450/100 ×16800

= 175600

area of TILES =s×s

= 20×20

= 400

according to the room length the area of tiles =400×10

= 4000

by ADDING in 4.5m = 4000×4.5

= 18000

the tiles will be adding = 18000-4000

= 14000

if the cost of putting the tiles in 1m= 131.40

then the cost of putting the tiles in 14000m = 14000×131.40

= 1839600