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The percentage of quantity of a radioactive material that remains after 5 half-lives will be .A. `1% `B. `3%`C. `5%`D. `20%` |
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Answer» Correct Answer - B `t=5T_n` `(5T_n)/(T_n)` `N=N_0 (1//2)` `N=N_0/32` `N(%) = 100/32 N_((0))=3%` |
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