Saved Bookmarks
| 1. |
The percentage of alcohol in a mixture of ¾ liter of pure water and x liters of 8% alcohol solution |
|
Answer» ong>GIVEN : a mixture of ¾ liter of pure water and x liters of 8% alcohol solution To find : The percentage of alcohol in mixture Solution: Water = 3/4 Litre => Water = 0.75 Litre x litre of 8% alcohol solution => alcohol = (8/100)x = 0.08x litre water in x litre of 8% alcohol solution = x - 0.08 = 0.92x litre Total mixture = x + 0.75 litre Total alcohol = 0.08x litre % of alcohol in mixture = 100 * (0.08x )/(x + 0.75) = 8x/(x + 0.75) = 8x/(x + 3/4) = 32x/(4x + 3) 32x/(4x + 3) % alcohol in a mixture of ¾ liter of pure water and x liters of 8% alcohol solution Learn More: mixture of liquid and B contains 70% of b by volume liquid of c us ... A vessel contains 20 % concentrated solution of Sulphuric ACID. If 50 ... |
|