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the PE Of SHM is 0.1sec after crossing the mean position is 1/4of it's total energy. then the period of it's? |
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Answer» T=0.6sExplanation:Firstly, this is a good question, Hoped you LIKED it too!!Total Energy of SHM is given by mω²A²and PE is given by mω²(A²-x²)Now; mω²(A²-x²)= (mω²A²)=>A²-x²==>X= -----(1)now ; x = ASIN(ωt) =Asin(ωt) ∴ωt= (0.1)= ∴T=3/5=0.6s hope this ANSWER is HELPFUL, if so please mark as Brainliest :) |
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