1.

The particle is executing S.H.M. on a line 4 cms long. If its velocity at mean position is 12 cm/sec its frequency in Hertz will be :​

Answer»

Answer:3/2pie

Explanation: here W= OMEGA

A=4CM

Vmean= 12CM/SEC

V=W UNDERROOTA^2-x^2  (x=0)

V=AW

12=4W

W=3

W=2PIE f

f=3/2pie



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