1.

The pair in which both species have the same magnetic moment (spin only value) is

Answer»

`[CR(H_2O)_6]^(2+) , [CoCl_4]^(2-)`
`[Cr(H_2O)_6]^(2+) , [FE(H_2O)_6]^(2+)`
`[Mn(H_2O)_6]^(2+) , [Cr(H_2O)_6]^(2+)`
`[CoCl_4]^(2-) , [Fe(H_2O)_6]^(2+)`

Solution :`[Cr(H_2O)_6]^(2+)=Cr^(2+) , 3d^4` = FOUR unpaired electrons
`[Fe(H_2O)_6]^(2+)= Fe^(2+) =3d^6` , Four unpaired electrons.
Hence, both the species have same magnetic MOMENT.


Discussion

No Comment Found

Related InterviewSolutions