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The packing fraction of a simple cubic structure is pi//6. Prove. |
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Answer» Solution :In a simple cube, the FACE edge length, a = 2R Number of atoms present in one unit cell = 1 Packing fraction = `("volume OCCUPIED by atoms" )/("VOLUMEOF theunitcell" ) =(4/3pir^(3))/(a^(3))=4/3(pir^(3))/(2r)^(3)=(pi)/(6)` |
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