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The packing fraction of a simple cubic structure is (pi)/(6). Prove. |
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Answer» Solution :In a SIMPLE CUBE, the face edge length, `a= 2r`. Number of atoms present in one unit cell `= 1` Packing Fraction `=("VOLUME occupied by atoms")/("Volume of the unit cell")=((4)/(3) pi r^(3))/( a^(3) ) = (4)/( 3) (pir^(3) )/( (2r)^(3))= (pi)/( 6) =0.524` |
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