1.

The oxide of an element possess the molecular formula M2O3. If the equivalent mass of the metal is 9, the molecular mass of the oxide will be-

Answer» SINCE valancy FACTOR of metal is 3 so
ATOMIC weight of metal = 3*equivalent mass
. . . . = 3*9=27
Atomic mass of O= 16 so O3 = 48
So the molecular weight of M2O3 = 2*27+3*16=102


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