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The oxidation state of phosphorous is minimum in(A) P4O6(B) NaH2PO2(C) PH3 (D)Na3PO4 |
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Answer» Hi there, The answer is C= PH3 The oxidation STATE for compounds O= -2 Na = +1 H= +1 A) P4O6 P= 2×6 ÷4 = +3 B) NaH2PO2 P= 2×2 - 3 = +1 C) PH3 P = -3 D) Na3PO4 P= 2×4 - 3 = +5 The minimum is 《C》 ♡ Hope the answer is helpful ♡ Plz mark it as brainliest |
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