1.

The oxidation state of nitrogen is highest in

Answer»

`N_(3)H`
`NH_(2)OH`
`N_(2)H_(2)`
`NH_(3)`

Solution :`3XX x+1 (1)=0`
`3x+1=0`
`3x=-1, IMPLIES x= -1/3` in `N_(2)H`
`x+2(+1)+1(-2)+1(1)=0`
`x=-1` in `NH_(2)OH`
`x xx 2+4(1)=0""x=-4/2=-2` in `N_(2)H_(4)`
`x+3(1)=0""x=-3` in `NH_(3)`
Hence, highest in `N_(3)H`.


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