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The oxidation number of xenon in `XeOF_(2)` isA. ZeroB. `2`C. `4`D. `3` |
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Answer» Correct Answer - C Suppose the oxidation state of `Xe` is `x.XeOF_(2)` `x+(-2)+2(-1)=0impliesx-2-2impliesx=4`. |
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