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The oxdidation number of sulphur is +4 isA. `H_(2)S`B. `CS_(2)`C. `Na_(2)SO_(4)`D. `Na_(2)SO_(3)` |
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Answer» Correct Answer - d `H_(2)S^(-2)` `CS_(2)^(-2)` `Na_(2)overset(+6)(SO)_(3)` `Na_(2)overset(+4)(SO)_(3)` |
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