1.

The osmotic pressure of blood is 7.47 bar at 300 K. To inject glucose to a patient intravenously, it has to be isotonic with blood. The concentration of glucose solution in gL–1 is _____(Molar mass of glucose = 180 g mol–1 R = 0.083 L bar K–1 mol–1 ) (Nearest integer)

Answer»

π = C.R.T.

7.47 = C x 0.083 x 300

C = 0.3 M

= 0.3 x 180 gL-1

 = 54 gL-1



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