The osmotic pressure exerted by a solution prepared by dissolving 2.0

1.	The osmotic pressure exerted by a solution prepared by dissolving 2.0 g of protein of molar mass 60 kg mol–1 in 200 mL of water at 27°C is _______ Pa. [integer value] (use R = 0.083 L bar mol–1 K –1 )
Answer» π = iCRT = \(\frac{1\times2}{60000\times0.2}\times0.083\times300\) = 0.00415 bar (\(\because\) 1 bar = 10⁵ Pa) So, 0.00415 x 10⁵ Pa = 415 Pa

The osmotic pressure exerted by a solution prepared by dissolving 2.0 g of protein of molar mass 60 kg mol–1 in 200 mL of water at 27°C is _______ Pa. [integer value] (use R = 0.083 L bar mol–1 K –1 )

Answer»

π = iCRT

= \(\frac{1\times2}{60000\times0.2}\times0.083\times300\)

= 0.00415 bar (\(\because\) 1 bar = 10⁵ Pa)

So, 0.00415 x 10⁵ Pa = 415 Pa

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The osmotic pressure exerted by a solution prepared by dissolving 2.0 g of protein of molar mass 60 kg mol–1 in 200 mL of water at 27°C is _______ Pa. [integer value] (use R = 0.083 L bar mol–1 K –1 )

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