1.

The oscillating magnetic field in a plane electromagnetic wave is given by  By = (8 x10-6)sin[2 x1011t + 300πx]T(i) Calculate the wavelength of the electromagnetic wave.(ii) Write down the expression for the oscillating electric field.

Answer»

(i) Standard equation of magnetic field is

By = B0sin(ωt + kx)T

Comparing this equation with the given equation, we get

B0 = 8 x 10-6T, ω = 2 x 1011 rad s-1, k = 2π/λ = 300π

wavelength  λ  = 2π/300π = 1/150m

(ii) E0B0c = 8 x 10-6 x 3 x 108 = 2.4 x 103Vm.

According to right hand system of vector E, vector B, vector K, the electric field oscillates along negative Z-axis, so equation is

Ez = - 2.4 x 103sin(2 x 1011t + 300πx)Vm-1.



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