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The oscillating magnetic field in a plane electromagnetic wave is given by By = (8 x10-6)sin[2 x1011t + 300πx]T(i) Calculate the wavelength of the electromagnetic wave.(ii) Write down the expression for the oscillating electric field. |
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Answer» (i) Standard equation of magnetic field is By = B0sin(ωt + kx)T Comparing this equation with the given equation, we get B0 = 8 x 10-6T, ω = 2 x 1011 rad s-1, k = 2π/λ = 300π wavelength λ = 2π/300π = 1/150m (ii) E0B0c = 8 x 10-6 x 3 x 108 = 2.4 x 103Vm. According to right hand system of vector E, vector B, vector K, the electric field oscillates along negative Z-axis, so equation is Ez = - 2.4 x 103sin(2 x 1011t + 300πx)Vm-1. |
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