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The order and degree of the differential equation \([1+(\frac{dx}{dy})^3]^\frac73 =7(\frac{d^2y}{dx^2})\) are respectively.(A) 2, 3 (B) 3, 2 (C) 2, 2 (D) 3, 3 |
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Answer» (A) 2,3 \([1+(\frac{dx}{dy})^3]^\frac73 =7(\frac{d^2y}{dx^2})\) Cubing on both sides, we get \([1+(\frac{dx}{dy})^3]^7 =7^3(\frac{d^2y}{dx^2})^3\) By definition of degree and order, Degree: 3 ; Order: 2 |
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