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The number of ways in which we can choose a committee from four men and six women so that the committee includes at least two men and exactly twice as many women as men is(A) 94(B) 126(C) 128 (D) None |
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Answer» Answer is (A) Number of men = 4; Number of women = 6 It is given that committee includes at least two men and exactly twice as many women as men. So, we can select either 2 men and 4 women or 3 men and 6 women. ∴ Required number of committee formed = 4C2 x 6C4 + 4C3 x 6C6 = 6×15 + 4×1=94 |
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