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The number of values of `k` for which the system of equations: `kx+(3k+2)y=4k` `(3k-1)x+(9k+1)y=4(k+1)` has no solution, areA. `0`B. `1`C. `2`D. `3` |
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Answer» Correct Answer - A `cancel (9k^(2))+k=cancel(9k^(2))+3k-2` `k=1` but it is not possible because at `k=1` there will be infinite solution. |
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