The number of value(s) of x satisfying the eqaution x2−6x+8=3+√1+x

1.	The number of value(s) of x satisfying the eqaution x2−6x+8=3+√1+x,x∈(3,∞) is
Answer» The number of value(s) of $x$ satisfying the eqaution $x^{2} - 6 x + 8 = 3 + \sqrt{1 + x}, x \in (3, \infty)$ is

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