1.

the number of turns per unit length of a long solenoid is 10. if it's average radius is 5 cm and it carries a current of 10A, then the ratio of fluxes densities at the centre and at the end on the axis will be​

Answer»

2.Explanation:The MAGNETIC FIELD at the center of the solenoid will be μ₀ni((sin90+sin90)/2) which will be μ₀ni. Since, the angles will be 90 and 90 for the center of the magnetic field.The magnetic field at the ends will be μ₀ni((sin90+sin0)/2) since the two angle of the end is 90 and 0 DEGREE so the magnetic field will be μ₀ni/2. THEREFORE, the ratio will be magnetic field at the center / magnetic field at the end.μ₀ni/μ₀ni/2 = 2.



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