The number of S2− ions present in 1 L of 0.1 M H2S [Ka(H2S)=10−21 – InterviewSolution

1.	The number of S2− ions present in 1 L of 0.1 M H2S [Ka(H2S)=10−21] solution having [H+]=0.1 M is:
Answer» The number of $S^{2 -}$ ions present in $1 L$ of $0.1 M$ $H_{2} S$ $[K_{a (H_{2} S)} = 10^{- 21}]$ solution having $[H^{+}] = 0.1 M$ is:

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