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The number of real number `lambda` for which the equality `(sin(lamdaalpha))/(sinalpha)-(cos(lamdaalpha))/(cosalpha)=lamda-1`, holds for all real `alpha` which are not integral multiples of `pi//2` is-A. 1B. 2C. 3D. Infinite |
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Answer» Correct Answer - B `(sin(lambdaalpha))/(sinalpha)-(cos(lambdaalpha))/(cosalpha)=lambda-1` By observation `sin(lambdaalpha)cosalpha-cos(lambdaalpha)sinalpha=(lambda-1)sinalphacosalpha` `sin(alpha-1)alpha=(lambda-1)sinalphacosalpha` clearly `lambda=1, lambda=3` is solution |
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