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The number of protons, neutrons and electrons in \(^{175}_{71}\)Lu , respectively, are : (1) 175, 104 and 71 (2) 71, 104 and 71 (3) 104, 71 and 71 (4) 71, 71 and 104 |
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Answer» (2) 71, 104 and 71 \(^{175}_{71}\)Lu p+ = 71 n0 = 175 – 71 = 104 e– = 71 |
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