1.

The number of protons, neutrons and electrons in \(^{175}_{71}\)Lu , respectively, are : (1) 175, 104 and 71 (2) 71, 104 and 71 (3) 104, 71 and 71 (4) 71, 71 and 104

Answer»

(2) 71, 104 and 71 

\(^{175}_{71}\)Lu

p+ = 71 

n0 = 175 – 71 = 104 

e = 71



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