1.

The number of nitrogen molecules present in 1 c.c of gas at NTP isi want with propeer explanation

Answer» 1 m³ = 1000 L
1000 cc = 1 L
1 cc = 10⁻³ L

so 22.4 L N₂ has 6.022 X 10²³ molecules

1 L N₂ has \frac{6.022*10^{23}}{22.4} molecules

10⁻³ N₂ has \frac{6.022*10^{23}*10^{-3}}{22.4} molecules

10⁻³ N₂ has 2.68*10^{19} molecules


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