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The number of moles of oxygen in 1 L of air containing 21% oxygen by volume, in standard conditions, is: |
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Answer» 0.0094Explanation:At standard CONDITIONS, 1 liter of air at 21% OXYGEN possesses 0.21 L of oxygen. Since at STP 1 mole of gas occupies 22.4 L, simply divide 0.21/22.4, to ARRIVE at 0.0094 moles of oxygen. |
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