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The number of moles of`KMnO_(4)` required to oxidise 2 mol of `FeC_(2)O_(4)` is acidin medium is :-A. 1.2B. 3.33C. 0.4D. 0.8 |
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Answer» Correct Answer - A `MnO_(4)^(-)+FeC_(2)O_(4)toMn^(+2)+Fe^(+3)+CO_(2)` Equivlents of `MnO_(4)^(-)` = Equivlents of ` FeC_(2)O_(4)` `X xx 5 = 2 xx3` X = 1.2mol |
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