The number of molecules in 4.25 g of NH, isapproximately(1) 4 x 1023 (

1.	The number of molecules in 4.25 g of NH, isapproximately(1) 4 x 1023 (2) 1.5 x 1023(3) 1 x 1023(4) 6 x 1023
Answer» ANSWER: Explanation: No.of Moles=Given Mass / MOLAR Mass. Given Mass =4.25 G =17/4. gMolar Mass of NH3 = 17g. So No.of Moles =17/4 ÷ 17= ¼. Therefore, No.of atoms=No.of Moles×6.022×10^23×Atomicity. Atomicity of NH3 is 4i.e. No.of atoms=¼ × 6.022×10^23 × 4 = 6.022×10^23..... Hence, the CORRECT option is 4....

The number of molecules in 4.25 g of NH, isapproximately(1) 4 x 1023 (2) 1.5 x 1023(3) 1 x 1023(4) 6 x 1023

Answer»

Explanation:

No.of Moles=Given Mass / MOLAR Mass.

Given Mass =4.25 G =17/4.

gMolar Mass of NH3 = 17g.

So No.of Moles =17/4 ÷ 17= ¼.

Therefore, No.of atoms=No.of Moles×6.022×10^23×Atomicity.

Atomicity of NH3 is 4i.e. No.of atoms=¼ × 6.022×10^23 × 4 = 6.022×10^23.....

Hence, the CORRECT option is 4....