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The number of halide ions in [Pt ( NH 3 ) 3 Cl 2 Br ] Cl is

Answer»

ong>ANSWER:

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Explanation:

[Pt(NH3)Cl2 Br]Cl⇌[Pt(NH3 )Cl2 Br] + +Cl −

The NUMBER of precipitable halide ions in the sample [Pt(NH3)Cl2Br]Cl will be 1 SINCE only 1 free chloride or halide ion is formed when dissolved in the solvent.

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