The number of gram-equivalent of h3po4 present in its 0.1 molar,250 ml

1.	The number of gram-equivalent of h3po4 present in its 0.1 molar,250 ml solution is
Answer» H3PO4 3+31 +64 = 98 , molecular MASS. 1 litre of 0.1 molar solution contains 98 x 0.1 = 9.8 g 250 ml contains 9.8/4 = 2.45 g eq. mass of H3PO4 = 98/3 = 32.67 g there FORE no.of equivalents 250 ml of 0.1 molar = 2.45/32.67 g = 0.075

The number of gram-equivalent of h3po4 present in its 0.1 molar,250 ml solution is

Answer»

H3PO4

3+31 +64 = 98 , molecular MASS.

1 litre of 0.1 molar solution contains 98 x 0.1 = 9.8 g

250 ml contains 9.8/4 = 2.45 g

eq. mass of H3PO4 = 98/3 = 32.67 g

there FORE no.of equivalents 250 ml of 0.1 molar = 2.45/32.67 g

= 0.075