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The number of four digit numbers with distinct digits is :(a) 9x9C3(B) 9x9P3(C)10C3(d) 10p3 |
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Answer» (b) The thousandth place can be filled up in 9 ways with any one of the digits 1, 2, 3, ...., 9. After that the other three places can be filled up in 9P3 ways, with any one of the remaining 9 digits including zero. Hence, the number of four digit numbers with distinct digits = 9x9p3 . |
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