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The number of Faradays(F) required to produce 20 g of calcium from molten CaCl2 (Atomic mass of Ca = 40 g mol–1) is : (1) 4 (2) 1 (3) 2 (4) 3 |
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Answer» (2) 1 Ca+2 + 2e– ® Ca(s) v.f. = 2 As per faraday's 1st law Charge passed in faraday = g.eq of product = ´20/40 x 2 = 1F w=ZQ. => Q=w/Z= 20/40/2 F = 1Fw=ZQ. => Q=w/Z = 20/40/2 F = 1FAs per faraday's 1st law Charge passed in faraday = g.eq of productw=ZQ. => Q=w/Z = 20/40/2 F = 1F As per faraday's 1st law Charge passed in faraday = g.eq of product |
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