The number of atoms present in 4.25 grams of NH3is approximately1) 23

1.	The number of atoms present in 4.25 grams of NH3is approximately1) 23 110 2) 23 5.1 10 3) 23
Answer» Step-by-step explanation: Answer. So 4.25 g ammonia will contain (6.022×10^23×4.25)/17 = 1.5×10^23 number of ammonia MOLECULES. Each molecule contain 4 atoms (1 N ATOM and 3 H atoms). So 4.25g ammonia will contain 1.5×10^23×4 = 6×10^23 number of atoms

The number of atoms present in 4.25 grams of NH3is approximately1) 23 110 2) 23 5.1 10 3) 23

Answer»

Step-by-step explanation:

Answer. So 4.25 g ammonia will contain (6.022×10^23×4.25)/17 = 1.5×10^23 number of ammonia MOLECULES. Each molecule contain 4 atoms (1 N ATOM and 3 H atoms). So 4.25g ammonia will contain 1.5×10^23×4 = 6×10^23 number of atoms

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The number of atoms present in 4.25 grams of NH3is approximately1) 23 110 2) 23 5.1 10 3) 23​

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The number of atoms present in 4.25 grams of NH3is approximately1) 23 110 2) 23 5.1 10 3) 23