The number of atoms in 100 g of a fcc crystal with density, d=10 gcm� – InterviewSolution

1.	The number of atoms in 100 g of a fcc crystal with density, d=10 gcm−3 and cell edge equal to 100 pm, is equal to:
Answer» The number of atoms in 100 g of a fcc crystal with density, $d = 10 {gcm}^{- 3}$ and cell edge equal to 100 pm, is equal to:

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