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The number of arrangement of the letters in the word 'FAILURE', so that vowels are always coming together is. |
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Answer» Answer: In WORD of 'FAILURE' vowels are A,I,U,E = 4 We arrange 7 word's ||| { _ _ _ _ _ _ _ } ||| ||| { A,I,U,E _ _ _ } ||| ~~~~~~ Total NUMBER of word formed when all vowels are always coming TOGETHER = 4P4 × 4P4 4P4 = vowels 4P4 = consonants Total number of ways = 4! × 4! 24 × 24 = 576 ways I hope its WORKING thanks |
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