the number fo electrons required to reduce chromium completely in `Cr_(2) O_(7) ^(2-) ` to `Cr_(3+)` in acidic meddium , isA. 5B. 3C. 6D. 2

the number fo electrons required to reduce chromium completely in `Cr_

1.	the number fo electrons required to reduce chromium completely in `Cr_(2) O_(7) ^(2-) ` to `Cr_(3+)` in acidic meddium , isA. 5B. 3C. 6D. 2
Answer» Correct Answer - C `Cr_(2) O_(7) ^(-2) +14H^(+)+6e^(-) to 2Cr^(+3) +7H_(2) O` `therefore ` no of electron = 6

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the number fo electrons required to reduce chromium completely in `Cr_(2) O_(7) ^(2-) ` to `Cr_(3+)` in acidic meddium , isA. 5B. 3C. 6D. 2

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