The number 405 and 1960, written as the product of their prime factors

1.	The number 405 and 1960, written as the product of their prime factors, are405= 34 × 5 and 1960= 23 × 5 × 72. Hence, find (i) the greatest whole number which is a factor of both 405 and 1960.(ii) the smallest whole number that is divisible by both 405 and 1960.
Answer» Step-by-step explanation: 405 = 3×135 = 3×3×45 = 3×3×3×15 = 3×3×3×3×5 1960 =2×980 =2×2×490 = 2×2×2×245 = 2×2×2×5×49 = 2×2×2×5×7×7 the greatest WHOLE number is 5 and SMALLEST whole number is also 5 which is FACTOR of both 406 and 1960.

The number 405 and 1960, written as the product of their prime factors, are405= 34 × 5 and 1960= 23 × 5 × 72. Hence, find (i) the greatest whole number which is a factor of both 405 and 1960.(ii) the smallest whole number that is divisible by both 405 and 1960.

Answer»

Step-by-step explanation:

405 = 3×135

= 3×3×45

= 3×3×3×15

= 3×3×3×3×5

1960 =2×980

=2×2×490

= 2×2×2×245

= 2×2×2×5×49

= 2×2×2×5×7×7

the greatest WHOLE number is 5 and SMALLEST whole number is also 5 which is FACTOR of both 406 and 1960.