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The nucleus 2310 Ne decays by β–emission. Write down the β-decay equation and determine the maximum kinetic energy of theelectrons emitted. Given that:m (2310 Ne ) = 22.994466 um (2311 Na ) = 22.089770 u. |
| Answer» The nucleus 2310 Ne decays by β–emission. Write down the β-decay equation and determine the maximum kinetic energy of theelectrons emitted. Given that:m (2310 Ne ) = 22.994466 um (2311 Na ) = 22.089770 u. | |