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The nth term of an arithmetic progressionis a=4n+ 5 then the god term is |
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Answer» QUESTION :- The nth term of an arithmetic progression is an=4n+5 then the 3rd term is ? Solution :- we know that,
so, → a + (n - 1)d = 4n + 5 → a + (n - 1)d = 4n - 4 + 4 + 5 → a + (n - 1)d = 9 + 4n - 4 → a + (n - 1)d = 9 + (n - 1)4 comparing we get,
therefore, → a3 = a + (3 - 1)d → a3 = 9 + 2*4 → a3 = 9 + 8 → a3 = 17 (Ans.) Learn more :- |
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