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The nth term of an arithmetic progression is an = 4n+5 then the 3rd term is |
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Answer» an-4n+5 SolUtIoNap is LET n-1 4n+5 4*1+5 4+5 =9 ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,, let n-2 4*2+5 8+5 =13 ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,, , ,,,,,,, let n-3 4*3+5 =17 ap is 9,13,17 ,,,,,,,,,,, HENCE third term is 17 verifyingan=a+(n-1)d 17=9+(n-1)4 17-9=(n-1)4. 8=(n-1)4 2=(n-1) 2+1=n 3=n hope its helpful |
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