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The normals at the ends of the latusrectum of the parabola `y^(2)=4ax" are (a, 2a) and (a, -2a)"`.A. `pi/6`B. `pi/4`C. `pi/3`D. `pi/2` |
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Answer» Correct Answer - D The coordinates of the end points of the latusrectum of the parabola `y^(2)=4ax` are (a, 2a) and (a, -2a). The equation of the normal at (a, 2a) is `y-2a=-(2a)/(2a)(x-a)or, x+y-3a=0" ...(i)"` The equation of the normal at (a, -2a) is `y+2a=(-2a)/(2a)(x-a)or, x-y-3a=0" ...(ii)"` Clearly, (i) and (ii) are perpendicular as the product of their slopes is -1. |
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