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The normal to the parabola `y^(2)=4x` at P (1, 2) meets the parabola again in Q, then coordinates of Q areA. (-6, 9)B. (9, -6)C. (-9, -6)D. (-6, -9) |
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Answer» Correct Answer - B Let the coordinates of P be `(t_(1)^(2), 2t_(1))`. But, the coordinates P are given as (1, 2). Therefore, `t_(!)=1`. Let the coordinates of Q be `(t_(2)^(2), 2t_(2))`. Then, `t_(2)=-t_(1)-2/t_(1)rArrt_(2)=-3` Hence, the coordinates of Q are (9, -6). |
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