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the normal to the curve y=f(x) at the point (3,4) makes an31 with the positive x-axis, then f'(3) is equal to |
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Answer» Given y = f(x) differentiating w.r.t x y' = f'(x) which is the slope of the tangent Hence the slope of the normal is - 1/f'(x) = 3pi/4 = -1 therefore f'(x) = 1 Hence f'(3) = 1 |
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