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The normal boiling point of water is 373 K. Vapour pressure of water at temperature 'T' is 19 mm Hg. If enthalpy of vaporisation is 40.67 kJ/mol , then temperature 'T' would be: (Use : log 2=0.3, R=8.3 J K−1mol−1) |
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Answer» The normal boiling point of water is 373 K. Vapour pressure of water at temperature 'T' is 19 mm Hg. If enthalpy of vaporisation is 40.67 kJ/mol , then temperature 'T' would be: |
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