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The near point of a hypermetropic eye is 1m .The power of the lens required to correct this defect is ______ (Assume that the near point of the normal eye is 25 cm |
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Answer» -OBJECT distance (u) = -25 cmImage distance (v) = -1 m = -100 cmTo find :-Nature and power of lens required to correct hypermetropia Concept :-The eye defect called hypermetropia and it is corrected by using convex lens.so,the person requires convex lens spectacles We will first calculate the FOCAL LENGTH of convex lens required in this case.Solution :-HENCE the focal length of the convex lens required will be 33.3 cm.Now,Hence,the power of convex lens required is 3.03 dioptres. |
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