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The natural number has prime factorization given by N=23⋅5x⋅7y, where x+y=5 and 1x+1y=56 (x>y). Then the number of even divisors of N (excluding N), is equal to |
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Answer» The natural number has prime factorization given by N=23⋅5x⋅7y, where x+y=5 and 1x+1y=56 (x>y). Then the number of even divisors of N (excluding N), is equal to |
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